Distance from Belgrade to Seen (Kreis 3)
Distance between Belgrade and Seen (Kreis 3) is 948 kilometers (589 miles).
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Distance Map Between Belgrade and Seen (Kreis 3)
Belgrade, Serbia ↔ Seen (Kreis 3), Zurich, Switzerland = 589 miles = 948 km.
How far is it between Belgrade and Seen (Kreis 3)
Belgrade is located in Serbia with (44.804,20.4651) coordinates and Seen (Kreis 3) is located in Switzerland with (47.4765,8.77) coordinates. The calculated flying distance from Belgrade to Seen (Kreis 3) is equal to 589 miles which is equal to 948 km.
| City/Place | Latitude and Longitude | GPS Coordinates |
|---|---|---|
| Belgrade | 44.804, 20.4651 | 44° 48´ 14.4360'' N 20° 27´ 54.4680'' E |
| Seen (Kreis 3) | 47.4765, 8.77 | 47° 28´ 35.2560'' N 8° 46´ 11.8560'' E |
Belgrade, Serbia
Related Distances from Belgrade
| Cities | Distance |
|---|---|
| Belgrade to Zuerich Kreis 7 | 1249 km |
| Belgrade to Dubendorf | 1245 km |
| Belgrade to La Chaux De Fonds | 1399 km |
| Belgrade to Oberwinterthur Kreis 2 | 1220 km |
| Belgrade to Zuerich Kreis 2 | 1275 km |
Seen (Kreis 3), Zurich, Switzerland
Related Distances to Seen (Kreis 3)
| Cities | Distance |
|---|---|
| Zuerich Kreis 9 to Seen Kreis 3 | 32 km |
| Zuerich Kreis 3 to Seen Kreis 3 | 33 km |
| Zuerich Kreis 7 to Seen Kreis 3 | 28 km |
| Zuerich Kreis 2 to Seen Kreis 3 | 35 km |
| Zuerich Kreis 10 to Seen Kreis 3 | 31 km |