Distance from Florida Ridge to Boynton Beach
Distance between Florida Ridge and Boynton Beach is 122 kilometers (76 miles).
122 km
76 miles
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Distance Map Between Florida Ridge and Boynton Beach
Florida Ridge, Tallahassee, United States ↔ Boynton Beach, Tallahassee, United States = 76 miles = 122 km.
How far is it between Florida Ridge and Boynton Beach
Florida Ridge is located in United States with (27.5803,-80.3867) coordinates and Boynton Beach is located in United States with (26.5254,-80.0664) coordinates. The calculated flying distance from Florida Ridge to Boynton Beach is equal to 76 miles which is equal to 122 km.
| City/Place | Latitude and Longitude | GPS Coordinates |
|---|---|---|
| Florida Ridge | 27.5803, -80.3867 | 27° 34´ 49.1160'' N 80° 23´ 12.1920'' W |
| Boynton Beach | 26.5254, -80.0664 | 26° 31´ 31.2600'' N 80° 3´ 59.1480'' W |
Florida Ridge, Tallahassee, United States
Related Distances from Florida Ridge
| Cities | Distance |
|---|---|
| Florida Ridge to Clearwater | 267 km |
| Florida Ridge to Delray Beach | 147 km |
| Florida Ridge to Carrollwood Village | 249 km |
| Florida Ridge to Allapattah | 214 km |
| Florida Ridge to Davie | 185 km |
Boynton Beach, Tallahassee, United States
Related Distances to Boynton Beach
| Cities | Distance |
|---|---|
| University to Boynton Beach | 348 km |
| Haines City to Boynton Beach | 277 km |
| South Miami Heights to Boynton Beach | 126 km |
| Ocala to Boynton Beach | 402 km |
| Estero to Boynton Beach | 241 km |