Distance from Guayaquil to Sibate
Distance between Guayaquil and Sibate is 974 kilometers (605 miles).
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605 miles
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Distance Map Between Guayaquil and Sibate
Guayaquil, Ecuador ↔ Sibate, , Colombia = 605 miles = 974 km.
Leaflet | © OpenStreetMap
How far is it between Guayaquil and Sibaté
Guayaquil is located in Ecuador with (-2.2058,-79.908) coordinates and Sibate is located in Colombia with (4.4843,-74.245) coordinates. The calculated flying distance from Guayaquil to Sibate is equal to 605 miles which is equal to 974 km.
| City/Place | Latitude and Longitude | GPS Coordinates |
|---|---|---|
| Guayaquil | -2.2058, -79.908 | 2° 12´ 21.0240'' S 79° 54´ 28.6200'' W |
| Sibate | 4.4843, -74.245 | 4° 29´ 3.3000'' N 74° 14´ 41.9640'' W |
Guayaquil, Ecuador
Related Distances from Guayaquil
| Cities | Distance |
|---|---|
| Guayaquil to Bogota | 1478 km |
| Guayaquil to Puerto Lopez | 1657 km |
| Guayaquil to Medellin | 1529 km |
| Guayaquil to Cali | 1116 km |
| Guayaquil to Cartagena | 2160 km |