Distance from Jacksonville to Arecibo
Distance between Jacksonville and Arecibo is 2003 kilometers (1245 miles).
2003 km
1245 miles
0 km
0 miles
Distance Map Between Jacksonville and Arecibo
Jacksonville, Tallahassee, United States ↔ Arecibo, Puerto Rico = 1245 miles = 2003 km.
How far is it between Jacksonville and Arecibo
Jacksonville is located in United States with (30.3322,-81.6557) coordinates and Arecibo is located in Puerto Rico with (18.4725,-66.7157) coordinates. The calculated flying distance from Jacksonville to Arecibo is equal to 1245 miles which is equal to 2003 km.
| City/Place | Latitude and Longitude | GPS Coordinates |
|---|---|---|
| Jacksonville | 30.3322, -81.6557 | 30° 19´ 55.8480'' N 81° 39´ 20.3400'' W |
| Arecibo | 18.4725, -66.7157 | 18° 28´ 20.8200'' N 66° 42´ 56.6280'' W |
Jacksonville, Tallahassee, United States
Related Distances from Jacksonville
| Cities | Distance |
|---|---|
| Jacksonville to Boynton Beach | 475 km |
| Jacksonville to Daytona Beach | 153 km |
| Jacksonville to Apopka | 224 km |
| Jacksonville to Dunedin 2 | 359 km |
| Jacksonville to Bloomingdale | 349 km |
Arecibo, Puerto Rico
Related Distances to Arecibo
| Cities | Distance |
|---|---|
| Ponce to Arecibo | 72 km |
| Humacao to Arecibo | 125 km |
| Carolina to Arecibo | 94 km |
| Trujillo Alto to Arecibo | 89 km |
| Yauco to Arecibo | 110 km |