Distance from Jacksonville to Bajos de Haina
Distance between Jacksonville and Bajos de Haina is 1770 kilometers (1100 miles).
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Distance Map Between Jacksonville and Bajos de Haina
Jacksonville, Tallahassee, United States ↔ Bajos de Haina, San Cristobal, Dominican Republic = 1100 miles = 1770 km.
How far is it between Jacksonville and Bajos de Haina
Jacksonville is located in United States with (30.3322,-81.6557) coordinates and Bajos de Haina is located in Dominican Republic with (18.4154,-70.0332) coordinates. The calculated flying distance from Jacksonville to Bajos de Haina is equal to 1100 miles which is equal to 1770 km.
| City/Place | Latitude and Longitude | GPS Coordinates |
|---|---|---|
| Jacksonville | 30.3322, -81.6557 | 30° 19´ 55.8480'' N 81° 39´ 20.3400'' W |
| Bajos de Haina | 18.4154, -70.0332 | 18° 24´ 55.3680'' N 70° 1´ 59.4120'' W |
Jacksonville, Tallahassee, United States
Related Distances from Jacksonville
| Cities | Distance |
|---|---|
| Jacksonville to Gainesville | 115 km |
| Jacksonville to Boca Raton | 496 km |
| Jacksonville to Fruit Cove | 40 km |
| Jacksonville to Ensley | 571 km |
| Jacksonville to Boynton Beach | 475 km |
Bajos de Haina, San Cristobal, Dominican Republic
Related Distances to Bajos de Haina
| Cities | Distance |
|---|---|
| Villa Altagracia to Bajos De Haina | 38 km |