Distance from Jacksonville to Campechuela
Distance between Jacksonville and Campechuela is 1206 kilometers (749 miles).
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749 miles
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Distance Map Between Jacksonville and Campechuela
Jacksonville, Tallahassee, United States ↔ Campechuela, Bayamo, Cuba = 749 miles = 1206 km.
How far is it between Jacksonville and Campechuela
Jacksonville is located in United States with (30.3322,-81.6557) coordinates and Campechuela is located in Cuba with (20.2342,-77.2789) coordinates. The calculated flying distance from Jacksonville to Campechuela is equal to 749 miles which is equal to 1206 km.
| City/Place | Latitude and Longitude | GPS Coordinates |
|---|---|---|
| Jacksonville | 30.3322, -81.6557 | 30° 19´ 55.8480'' N 81° 39´ 20.3400'' W |
| Campechuela | 20.2342, -77.2789 | 20° 14´ 3.0120'' N 77° 16´ 44.0040'' W |
Jacksonville, Tallahassee, United States
Related Distances from Jacksonville
| Cities | Distance |
|---|---|
| Jacksonville to Boston | 1840 km |
| Jacksonville to Immokalee | 491 km |
| Jacksonville to Glenvar Heights | 574 km |
| Jacksonville to Carol City | 536 km |
| Jacksonville to Fountainebleau | 572 km |