Distance from Jacksonville to Guaimaro
Distance between Jacksonville and Guaimaro is 1118 kilometers (695 miles).
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695 miles
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Distance Map Between Jacksonville and Guaimaro
Jacksonville, Tallahassee, United States ↔ Guaimaro, Camaguey, Cuba = 695 miles = 1118 km.
How far is it between Jacksonville and Guáimaro
Jacksonville is located in United States with (30.3322,-81.6557) coordinates and Guaimaro is located in Cuba with (21.0518,-77.3502) coordinates. The calculated flying distance from Jacksonville to Guaimaro is equal to 695 miles which is equal to 1118 km.
| City/Place | Latitude and Longitude | GPS Coordinates |
|---|---|---|
| Jacksonville | 30.3322, -81.6557 | 30° 19´ 55.8480'' N 81° 39´ 20.3400'' W |
| Guaimaro | 21.0518, -77.3502 | 21° 3´ 6.3360'' N 77° 21´ 0.7560'' W |
Jacksonville, Tallahassee, United States
Related Distances from Jacksonville
| Cities | Distance |
|---|---|
| Jacksonville to Haines City | 288 km |
| Jacksonville to Cooper City | 527 km |
| Jacksonville to Cocoa | 249 km |
| Jacksonville to Dania Beach | 537 km |
| Jacksonville to Hollywood 2 | 537 km |
Guaimaro, Camaguey, Cuba
Related Distances to Guaimaro
| Cities | Distance |
|---|---|
| Nuevitas to Guaimaro | 66 km |
| Esmeralda to Guaimaro | 144 km |
| Santa Cruz Del Sur to Guaimaro | 117 km |
| Florida to Guaimaro | 120 km |
| Jimaguayu to Guaimaro | 69 km |