Distance from Jacksonville to Rio Guayabal de Yateras
Distance between Jacksonville and Rio Guayabal de Yateras is 1293 kilometers (803 miles).
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Distance Map Between Jacksonville and Rio Guayabal de Yateras
Jacksonville, Tallahassee, United States ↔ Rio Guayabal de Yateras, Guantanamo, Cuba = 803 miles = 1293 km.
How far is it between Jacksonville and Río Guayabal de Yateras
Jacksonville is located in United States with (30.3322,-81.6557) coordinates and Rio Guayabal de Yateras is located in Cuba with (20.3667,-75.0167) coordinates. The calculated flying distance from Jacksonville to Rio Guayabal de Yateras is equal to 803 miles which is equal to 1293 km.
| City/Place | Latitude and Longitude | GPS Coordinates |
|---|---|---|
| Jacksonville | 30.3322, -81.6557 | 30° 19´ 55.8480'' N 81° 39´ 20.3400'' W |
| Rio Guayabal de Yateras | 20.3667, -75.0167 | 20° 22´ 0.0120'' N 75° 1´ 0.0120'' W |
Jacksonville, Tallahassee, United States
Related Distances from Jacksonville
| Cities | Distance |
|---|---|
| Jacksonville to Apopka | 224 km |
| Jacksonville to Carrollwood | 313 km |
| Jacksonville to Golden Glades | 539 km |
| Jacksonville to Dunedin 2 | 359 km |
| Jacksonville to Flagami | 567 km |
Rio Guayabal de Yateras, Guantanamo, Cuba
Related Distances to Rio Guayabal de Yateras
| Cities | Distance |
|---|---|
| Baracoa to Rio Guayabal De Yateras | 187 km |
| Maisi to Rio Guayabal De Yateras | 193 km |