Distance from Jacksonville to Sabaneta
Distance between Jacksonville and Sabaneta is 1591 kilometers (989 miles).
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Distance Map Between Jacksonville and Sabaneta
Jacksonville, Tallahassee, United States ↔ Sabaneta, Dominican Republic = 989 miles = 1591 km.
How far is it between Jacksonville and Sabaneta
Jacksonville is located in United States with (30.3322,-81.6557) coordinates and Sabaneta is located in Dominican Republic with (19.4779,-71.3413) coordinates. The calculated flying distance from Jacksonville to Sabaneta is equal to 989 miles which is equal to 1591 km.
| City/Place | Latitude and Longitude | GPS Coordinates |
|---|---|---|
| Jacksonville | 30.3322, -81.6557 | 30° 19´ 55.8480'' N 81° 39´ 20.3400'' W |
| Sabaneta | 19.4779, -71.3413 | 19° 28´ 40.5480'' N 71° 20´ 28.5000'' W |
Jacksonville, Tallahassee, United States
Related Distances from Jacksonville
| Cities | Distance |
|---|---|
| Jacksonville to Boston | 1840 km |
| Jacksonville to Cooper City | 527 km |
| Jacksonville to Homestead | 613 km |
| Jacksonville to Fountainebleau | 572 km |
| Jacksonville to Florida Ridge | 349 km |
Sabaneta, Dominican Republic
Related Distances to Sabaneta
| Cities | Distance |
|---|---|
| Cotui to Sabaneta 2 | 185 km |
| La Romana to Sabaneta 2 | 368 km |
| Concepcion De La Vega to Sabaneta 2 | 129 km |
| Azua to Sabaneta 2 | 337 km |
| Bani to Sabaneta 2 | 286 km |