Distance from Jacksonville to Salcedo
Distance between Jacksonville and Salcedo is 1662 kilometers (1033 miles).
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Distance Map Between Jacksonville and Salcedo
Jacksonville, Tallahassee, United States ↔ Salcedo, Dominican Republic = 1033 miles = 1662 km.
How far is it between Jacksonville and Salcedo
Jacksonville is located in United States with (30.3322,-81.6557) coordinates and Salcedo is located in Dominican Republic with (19.3776,-70.4176) coordinates. The calculated flying distance from Jacksonville to Salcedo is equal to 1033 miles which is equal to 1662 km.
City/Place | Latitude and Longitude | GPS Coordinates |
---|---|---|
Jacksonville | 30.3322, -81.6557 | 30° 19´ 55.8480'' N 81° 39´ 20.3400'' W |
Salcedo | 19.3776, -70.4176 | 19° 22´ 39.4320'' N 70° 25´ 3.4320'' W |
Jacksonville, Tallahassee, United States
Related Distances from Jacksonville
Cities | Distance |
---|---|
Jacksonville to Bradenton | 413 km |
Jacksonville to Gainesville | 115 km |
Jacksonville to Cape Coral | 520 km |
Jacksonville to Bartow | 331 km |
Jacksonville to Debary | 189 km |
Salcedo, Dominican Republic
Related Distances to Salcedo
Cities | Distance |
---|---|
Moca to Salcedo | 16 km |
Bani to Salcedo | 178 km |
Dajabon to Salcedo | 189 km |
Nagua to Salcedo | 93 km |
Concepcion De La Vega to Salcedo | 26 km |