Distance from Kinston to Jacksonville

Distance between Kinston and Jacksonville is 58 kilometers (36 miles).
Driving distance from Kinston to Jacksonville is 69 kilometers (43 miles).

58 km

36 miles

69 km

43 miles

Distance Map Between Kinston and Jacksonville

Kinston, Raleigh, United States ↔ Jacksonville, Raleigh, United States = 36 miles = 58 km.

How far is it between Kinston and Jacksonville

Kinston is located in United States with (35.2627,-77.5816) coordinates and Jacksonville is located in United States with (34.7541,-77.4302) coordinates. The calculated flying distance from Kinston to Jacksonville is equal to 36 miles which is equal to 58 km.

If you want to go by car, the driving distance between Kinston and Jacksonville is 68.5 km. If you ride your car with an average speed of 112 kilometers/hour (70 miles/h), travel time will be 00 hours 36 minutes. Please check the avg. speed travel time table on the right for various options.
Difference between fly and go by a car is 11 km.

City/Place	Latitude and Longitude	GPS Coordinates
Kinston	35.2627, -77.5816	35° 15´ 45.5760'' N 77° 34´ 53.9040'' W
Jacksonville	34.7541, -77.4302	34° 45´ 14.5800'' N 77° 25´ 48.8640'' W

Estimated Travel Time Between Kinston and Jacksonville

Average Speed	Travel Time
30 mph (48 km/h)	01 hours 25 minutes
40 mph (64 km/h)	01 hours 04 minutes
50 mph (80 km/h)	00 hours 51 minutes
60 mph (97 km/h)	00 hours 42 minutes
70 mph (112 km/h)	00 hours 36 minutes
75 mph (120 km/h)	00 hours 34 minutes

Kinston, Raleigh, United States

Related Distances from Kinston

Cities	Distance
Kinston to Clemmons	313 km
Kinston to Asheville	534 km
Kinston to Kannapolis	359 km
Kinston to Boone	432 km
Kinston to Asheboro	240 km

Jacksonville, Raleigh, United States

Related Distances to Jacksonville

Cities	Distance
Morrisville to Jacksonville 2	214 km
Shelby 2 to Jacksonville 2	472 km
Wilmington to Jacksonville 2	93 km
Kernersville to Jacksonville 2	342 km
Sanford 2 to Jacksonville 2	207 km