Distance from Lake Ridge to Christiansburg
Distance between Lake Ridge and Christiansburg is 323 kilometers (201 miles).
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201 miles
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Distance Map Between Lake Ridge and Christiansburg
Lake Ridge, Richmond, United States ↔ Christiansburg, Richmond, United States = 201 miles = 323 km.
How far is it between Lake Ridge and Christiansburg
Lake Ridge is located in United States with (38.6879,-77.2978) coordinates and Christiansburg is located in United States with (37.1299,-80.4089) coordinates. The calculated flying distance from Lake Ridge to Christiansburg is equal to 201 miles which is equal to 323 km.
| City/Place | Latitude and Longitude | GPS Coordinates |
|---|---|---|
| Lake Ridge | 38.6879, -77.2978 | 38° 41´ 16.4040'' N 77° 17´ 51.9360'' W |
| Christiansburg | 37.1299, -80.4089 | 37° 7´ 47.4600'' N 80° 24´ 32.1840'' W |
Lake Ridge, Richmond, United States
Related Distances from Lake Ridge
| Cities | Distance |
|---|---|
| Lake Ridge to East Hampton | 257 km |
| Lake Ridge to Alexandria 2 | 35 km |
| Lake Ridge to Annandale | 29 km |
| Lake Ridge to Colonial Heights | 174 km |
| Lake Ridge to Chesapeake | 283 km |
Christiansburg, Richmond, United States
Related Distances to Christiansburg
| Cities | Distance |
|---|---|
| Oakton to Christiansburg | 397 km |
| Short Pump to Christiansburg | 322 km |
| Newport News to Christiansburg | 466 km |
| Hybla Valley to Christiansburg | 430 km |
| Lincolnia to Christiansburg | 420 km |