Distance from Lexington to Camaguey
Distance between Lexington and Camaguey is 1622 kilometers (1008 miles).
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1008 miles
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Distance Map Between Lexington and Camaguey
Lexington, Raleigh, United States ↔ Camaguey, Cuba = 1008 miles = 1622 km.
Leaflet | © OpenStreetMap
How far is it between Lexington and Camagüey
Lexington is located in United States with (35.824,-80.2534) coordinates and Camaguey is located in Cuba with (21.3808,-77.9169) coordinates. The calculated flying distance from Lexington to Camaguey is equal to 1008 miles which is equal to 1622 km.
| City/Place | Latitude and Longitude | GPS Coordinates |
|---|---|---|
| Lexington | 35.824, -80.2534 | 35° 49´ 26.5080'' N 80° 15´ 12.1680'' W |
| Camaguey | 21.3808, -77.9169 | 21° 22´ 50.9880'' N 77° 55´ 0.9840'' W |
Lexington, Raleigh, United States
Related Distances from Lexington
| Cities | Distance |
|---|---|
| Lexington 3 to Asheville | 228 km |
| Lexington 3 to Concord 2 | 64 km |
| Lexington 3 to Charlotte | 96 km |
| Lexington 3 to Chapel Hill | 134 km |
| Lexington 3 to Greensboro | 57 km |
Camaguey, Cuba
Related Distances to Camaguey
| Cities | Distance |
|---|---|
| Bayamo to Camaguey | 209 km |
| Artemisa to Camaguey | 594 km |