Distance from Lexington-Fayette to Havana
Distance between Lexington-Fayette and Havana is 1670 kilometers (1038 miles).
1670 km
1038 miles
0 km
0 miles
Distance Map Between Lexington-Fayette and Havana
Lexington-Fayette, Frankfort, United States ↔ Havana, Cuba = 1038 miles = 1670 km.
How far is it between Lexington-Fayette and Havana
Lexington-Fayette is located in United States with (38.0498,-84.4586) coordinates and Havana is located in Cuba with (23.133,-82.383) coordinates. The calculated flying distance from Lexington-Fayette to Havana is equal to 1038 miles which is equal to 1670 km.
| City/Place | Latitude and Longitude | GPS Coordinates |
|---|---|---|
| Lexington-Fayette | 38.0498, -84.4586 | 38° 2´ 59.2800'' N 84° 27´ 30.7800'' W |
| Havana | 23.133, -82.383 | 23° 7´ 58.8720'' N 82° 22´ 58.9440'' W |
Lexington-Fayette, Frankfort, United States
Related Distances from Lexington-Fayette
| Cities | Distance |
|---|---|
| Lexington Fayette to Elizabethtown | 143 km |
| Lexington Fayette to Paducah | 415 km |
| Lexington Fayette to Danville 4 | 63 km |
| Lexington Fayette to Ashland 2 | 197 km |
| Lexington Fayette to Hopkinsville | 341 km |
Havana, Cuba
Related Distances to Havana
| Cities | Distance |
|---|---|
| Holguin to Havana | 752 km |
| Bayamo to Havana | 755 km |
| Guantanamo to Havana | 930 km |
| Artemisa to Havana | 67 km |
| Camaguey to Havana | 549 km |