Distance Calculator

Distance from Minnetonka to Champlin

Distance between Minnetonka and Champlin is 32 kilometers (20 miles).
Driving distance from Minnetonka to Champlin is 40 kilometers (25 miles).

air 32 km
air 20 miles
car 40 km
car 25 miles

Distance Map Between Minnetonka and Champlin

Minnetonka, Saint Paul, United StatesChamplin, Saint Paul, United States = 20 miles = 32 km.

How far is it between Minnetonka and Champlin

Minnetonka is located in United States with (44.9133,-93.5033) coordinates and Champlin is located in United States with (45.1889,-93.3975) coordinates. The calculated flying distance from Minnetonka to Champlin is equal to 20 miles which is equal to 32 km.

If you want to go by car, the driving distance between Minnetonka and Champlin is 40.27 km. If you ride your car with an average speed of 112 kilometers/hour (70 miles/h), travel time will be 00 hours 21 minutes. Please check the avg. speed travel time table on the right for various options.
Difference between fly and go by a car is 8 km.

City/PlaceLatitude and LongitudeGPS Coordinates
Minnetonka 44.9133, -93.5033 44° 54´ 47.8800'' N
93° 30´ 11.8440'' W
Champlin 45.1889, -93.3975 45° 11´ 19.8600'' N
93° 23´ 50.8200'' W

Estimated Travel Time Between Minnetonka and Champlin

Average SpeedTravel Time
30 mph (48 km/h) 00 hours 50 minutes
40 mph (64 km/h) 00 hours 37 minutes
50 mph (80 km/h) 00 hours 30 minutes
60 mph (97 km/h) 00 hours 24 minutes
70 mph (112 km/h) 00 hours 21 minutes
75 mph (120 km/h) 00 hours 20 minutes
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