Distance from Morgan Hill to Okanagan

Distance between Morgan Hill and Okanagan is 1483 kilometers (921 miles).
Driving distance from Morgan Hill to Okanagan is 1948 kilometers (1210 miles).

1483 km

921 miles

1948 km

1210 miles

Distance Map Between Morgan Hill and Okanagan

Morgan Hill, Sacramento, United States ↔ Okanagan, Victoria, Canada = 921 miles = 1483 km.

How far is it between Morgan Hill and Okanagan

Morgan Hill is located in United States with (37.1305,-121.6544) coordinates and Okanagan is located in Canada with (50.3639,-119.35) coordinates. The calculated flying distance from Morgan Hill to Okanagan is equal to 921 miles which is equal to 1483 km.

If you want to go by car, the driving distance between Morgan Hill and Okanagan is 1948.06 km. If you ride your car with an average speed of 112 kilometers/hour (70 miles/h), travel time will be 17 hours 23 minutes. Please check the avg. speed travel time table on the right for various options.
Difference between fly and go by a car is 465 km.

City/Place	Latitude and Longitude	GPS Coordinates
Morgan Hill	37.1305, -121.6544	37° 7´ 49.8000'' N 121° 39´ 15.8040'' W
Okanagan	50.3639, -119.35	50° 21´ 49.8960'' N 119° 20´ 59.8920'' W

Estimated Travel Time Between Morgan Hill and Okanagan

Average Speed	Travel Time
30 mph (48 km/h)	40 hours 35 minutes
40 mph (64 km/h)	30 hours 26 minutes
50 mph (80 km/h)	24 hours 21 minutes
60 mph (97 km/h)	20 hours 04 minutes
70 mph (112 km/h)	17 hours 23 minutes
75 mph (120 km/h)	16 hours 14 minutes

Morgan Hill, Sacramento, United States

Related Distances from Morgan Hill

Cities	Distance
Morgan Hill to Calgary	2167 km
Morgan Hill to Victoria	1510 km
Morgan Hill to Vancouver	1603 km
Morgan Hill to Burnaby	1598 km
Morgan Hill to Saskatoon	2760 km

Okanagan, Victoria, Canada

Related Distances to Okanagan

Cities	Distance
Camas 2 to Okanagan	853 km
Palo Alto to Okanagan	1920 km
Minot to Okanagan	1683 km
Highland 3 to Okanagan	1636 km
Walnut Creek to Okanagan	1842 km