Distance Calculator

Distance from San Benito to Cedar Hill

Distance between San Benito and Cedar Hill is 721 kilometers (448 miles).
Driving distance from San Benito to Cedar Hill is 828 kilometers (514 miles).

air 721 km
air 448 miles
car 828 km
car 514 miles

Distance Map Between San Benito and Cedar Hill

San Benito, Austin, United StatesCedar Hill, Austin, United States = 448 miles = 721 km.

How far is it between San Benito and Cedar Hill

San Benito is located in United States with (26.1326,-97.6311) coordinates and Cedar Hill is located in United States with (32.5885,-96.9561) coordinates. The calculated flying distance from San Benito to Cedar Hill is equal to 448 miles which is equal to 721 km.

If you want to go by car, the driving distance between San Benito and Cedar Hill is 827.92 km. If you ride your car with an average speed of 112 kilometers/hour (70 miles/h), travel time will be 07 hours 23 minutes. Please check the avg. speed travel time table on the right for various options.
Difference between fly and go by a car is 107 km.

City/PlaceLatitude and LongitudeGPS Coordinates
San Benito 26.1326, -97.6311 26° 7´ 57.2880'' N
97° 37´ 51.9600'' W
Cedar Hill 32.5885, -96.9561 32° 35´ 18.4920'' N
96° 57´ 22.0320'' W

Estimated Travel Time Between San Benito and Cedar Hill

Average SpeedTravel Time
30 mph (48 km/h) 17 hours 14 minutes
40 mph (64 km/h) 12 hours 56 minutes
50 mph (80 km/h) 10 hours 20 minutes
60 mph (97 km/h) 08 hours 32 minutes
70 mph (112 km/h) 07 hours 23 minutes
75 mph (120 km/h) 06 hours 53 minutes
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