Distance from San Pablo to Okanagan
Distance between San Pablo and Okanagan is 1399 kilometers (869 miles).
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869 miles
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Distance Map Between San Pablo and Okanagan
San Pablo, Sacramento, United States ↔ Okanagan, Victoria, Canada = 869 miles = 1399 km.
How far is it between San Pablo and Okanagan
San Pablo is located in United States with (37.9622,-122.3455) coordinates and Okanagan is located in Canada with (50.3639,-119.35) coordinates. The calculated flying distance from San Pablo to Okanagan is equal to 869 miles which is equal to 1399 km.
| City/Place | Latitude and Longitude | GPS Coordinates |
|---|---|---|
| San Pablo | 37.9622, -122.3455 | 37° 57´ 43.7400'' N 122° 20´ 43.9080'' W |
| Okanagan | 50.3639, -119.35 | 50° 21´ 49.8960'' N 119° 20´ 59.8920'' W |
San Pablo, Sacramento, United States
Related Distances from San Pablo
| Cities | Distance |
|---|---|
| San Pablo 2 to Calgary | 2068 km |
| San Pablo 2 to Ontario | 673 km |
| San Pablo 2 to Victoria | 1402 km |
| San Pablo 2 to Surrey | 1463 km |
| San Pablo 2 to Ladner | 1482 km |
Okanagan, Victoria, Canada
Related Distances to Okanagan
| Cities | Distance |
|---|---|
| Bayside to Okanagan | 1499 km |
| Aurora to Okanagan | 2198 km |
| Rosemont to Okanagan | 1795 km |
| Bainbridge Island to Okanagan | 579 km |
| Kalispell to Okanagan | 744 km |