Distance Calculator

Distance from Sanford to Deerfield Beach

Distance between Sanford and Deerfield Beach is 299 kilometers (186 miles).
Driving distance from Sanford to Deerfield Beach is 341 kilometers (212 miles).

air 299 km
air 186 miles
car 341 km
car 212 miles

Distance Map Between Sanford and Deerfield Beach

Sanford, Tallahassee, United StatesDeerfield Beach, Tallahassee, United States = 186 miles = 299 km.

How far is it between Sanford and Deerfield Beach

Sanford is located in United States with (28.8006,-81.2731) coordinates and Deerfield Beach is located in United States with (26.3184,-80.0998) coordinates. The calculated flying distance from Sanford to Deerfield Beach is equal to 186 miles which is equal to 299 km.

If you want to go by car, the driving distance between Sanford and Deerfield Beach is 340.58 km. If you ride your car with an average speed of 112 kilometers/hour (70 miles/h), travel time will be 03 hours 02 minutes. Please check the avg. speed travel time table on the right for various options.
Difference between fly and go by a car is 42 km.

City/PlaceLatitude and LongitudeGPS Coordinates
Sanford 28.8006, -81.2731 28° 48´ 1.9800'' N
81° 16´ 23.2320'' W
Deerfield Beach 26.3184, -80.0998 26° 19´ 6.2760'' N
80° 5´ 59.1720'' W

Estimated Travel Time Between Sanford and Deerfield Beach

Average SpeedTravel Time
30 mph (48 km/h) 07 hours 05 minutes
40 mph (64 km/h) 05 hours 19 minutes
50 mph (80 km/h) 04 hours 15 minutes
60 mph (97 km/h) 03 hours 30 minutes
70 mph (112 km/h) 03 hours 02 minutes
75 mph (120 km/h) 02 hours 50 minutes
Please Share Your Comments