Distance Calculator

Distance from Sayreville Junction to Fords

Distance between Sayreville Junction and Fords is 7 kilometers (4 miles).
Driving distance from Sayreville Junction to Fords is 11 kilometers (7 miles).

air 7 km
air 4 miles
car 11 km
car 7 miles

Distance Map Between Sayreville Junction and Fords

Sayreville Junction, Trenton, United StatesFords, Trenton, United States = 4 miles = 7 km.

How far is it between Sayreville Junction and Fords

Sayreville Junction is located in United States with (40.4654,-74.3304) coordinates and Fords is located in United States with (40.5293,-74.316) coordinates. The calculated flying distance from Sayreville Junction to Fords is equal to 4 miles which is equal to 7 km.

If you want to go by car, the driving distance between Sayreville Junction and Fords is 11.45 km. If you ride your car with an average speed of 112 kilometers/hour (70 miles/h), travel time will be 00 hours 06 minutes. Please check the avg. speed travel time table on the right for various options.
Difference between fly and go by a car is 4 km.

City/PlaceLatitude and LongitudeGPS Coordinates
Sayreville Junction 40.4654, -74.3304 40° 27´ 55.3680'' N
74° 19´ 49.5480'' W
Fords 40.5293, -74.316 40° 31´ 45.3720'' N
74° 18´ 57.5280'' W

Estimated Travel Time Between Sayreville Junction and Fords

Average SpeedTravel Time
30 mph (48 km/h) 00 hours 14 minutes
40 mph (64 km/h) 00 hours 10 minutes
50 mph (80 km/h) 00 hours 08 minutes
60 mph (97 km/h) 00 hours 07 minutes
70 mph (112 km/h) 00 hours 06 minutes
75 mph (120 km/h) 00 hours 05 minutes
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