Distance from Sayreville to Jackson

Distance between Sayreville and Jackson is 87 kilometers (54 miles).
Driving distance from Sayreville to Jackson is 103 kilometers (64 miles).

87 km

54 miles

103 km

64 miles

Distance Map Between Sayreville and Jackson

Sayreville, Trenton, United States ↔ Jackson, Trenton, United States = 54 miles = 87 km.

How far is it between Sayreville and Jackson

Sayreville is located in United States with (40.4593,-74.361) coordinates and Jackson is located in United States with (39.7765,-74.8624) coordinates. The calculated flying distance from Sayreville to Jackson is equal to 54 miles which is equal to 87 km.

If you want to go by car, the driving distance between Sayreville and Jackson is 103.12 km. If you ride your car with an average speed of 112 kilometers/hour (70 miles/h), travel time will be 00 hours 55 minutes. Please check the avg. speed travel time table on the right for various options.
Difference between fly and go by a car is 16 km.

City/Place	Latitude and Longitude	GPS Coordinates
Sayreville	40.4593, -74.361	40° 27´ 33.3720'' N 74° 21´ 39.5280'' W
Jackson	39.7765, -74.8624	39° 46´ 35.4000'' N 74° 51´ 44.5680'' W

Estimated Travel Time Between Sayreville and Jackson

Average Speed	Travel Time
30 mph (48 km/h)	02 hours 08 minutes
40 mph (64 km/h)	01 hours 36 minutes
50 mph (80 km/h)	01 hours 17 minutes
60 mph (97 km/h)	01 hours 03 minutes
70 mph (112 km/h)	00 hours 55 minutes
75 mph (120 km/h)	00 hours 51 minutes

Sayreville, Trenton, United States

Related Distances from Sayreville

Cities	Distance
Sayreville to Paramus	71 km
Sayreville to Perth Amboy	12 km
Sayreville to Piscataway	10 km
Sayreville to Mount Laurel	94 km
Sayreville to Passaic	61 km

Jackson, Trenton, United States

Related Distances to Jackson

Cities	Distance
Vineland to Jackson 3	43 km
Sicklerville to Jackson 3	14 km
East Brunswick to Jackson 3	95 km
Rahway to Jackson 3	121 km
Rutherford to Jackson 3	149 km