Distance Calculator

Distance from Seaford to East Patchogue

Distance between Seaford and East Patchogue is 43 kilometers (27 miles).
Driving distance from Seaford to East Patchogue is 51 kilometers (31 miles).

air 43 km
air 27 miles
car 51 km
car 31 miles

Distance Map Between Seaford and East Patchogue

Seaford, Albany, United StatesEast Patchogue, Albany, United States = 27 miles = 43 km.

How far is it between Seaford and East Patchogue

Seaford is located in United States with (40.6659,-73.4882) coordinates and East Patchogue is located in United States with (40.767,-72.9962) coordinates. The calculated flying distance from Seaford to East Patchogue is equal to 27 miles which is equal to 43 km.

If you want to go by car, the driving distance between Seaford and East Patchogue is 50.68 km. If you ride your car with an average speed of 112 kilometers/hour (70 miles/h), travel time will be 00 hours 27 minutes. Please check the avg. speed travel time table on the right for various options.
Difference between fly and go by a car is 8 km.

City/PlaceLatitude and LongitudeGPS Coordinates
Seaford 40.6659, -73.4882 40° 39´ 57.3480'' N
73° 29´ 17.4480'' W
East Patchogue 40.767, -72.9962 40° 46´ 1.3440'' N
72° 59´ 46.3920'' W

Estimated Travel Time Between Seaford and East Patchogue

Average SpeedTravel Time
30 mph (48 km/h) 01 hours 03 minutes
40 mph (64 km/h) 00 hours 47 minutes
50 mph (80 km/h) 00 hours 38 minutes
60 mph (97 km/h) 00 hours 31 minutes
70 mph (112 km/h) 00 hours 27 minutes
75 mph (120 km/h) 00 hours 25 minutes
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