Distance Calculator

Distance from Seaford to Mount Vernon

Distance between Seaford and Mount Vernon is 40 kilometers (25 miles).
Driving distance from Seaford to Mount Vernon is 59 kilometers (37 miles).

air 40 km
air 25 miles
car 59 km
car 37 miles

Distance Map Between Seaford and Mount Vernon

Seaford, Albany, United StatesMount Vernon, Albany, United States = 25 miles = 40 km.

How far is it between Seaford and Mount Vernon

Seaford is located in United States with (40.6659,-73.4882) coordinates and Mount Vernon is located in United States with (40.9126,-73.8371) coordinates. The calculated flying distance from Seaford to Mount Vernon is equal to 25 miles which is equal to 40 km.

If you want to go by car, the driving distance between Seaford and Mount Vernon is 58.81 km. If you ride your car with an average speed of 112 kilometers/hour (70 miles/h), travel time will be 00 hours 31 minutes. Please check the avg. speed travel time table on the right for various options.
Difference between fly and go by a car is 19 km.

City/PlaceLatitude and LongitudeGPS Coordinates
Seaford 40.6659, -73.4882 40° 39´ 57.3480'' N
73° 29´ 17.4480'' W
Mount Vernon 40.9126, -73.8371 40° 54´ 45.3600'' N
73° 50´ 13.4880'' W

Estimated Travel Time Between Seaford and Mount Vernon

Average SpeedTravel Time
30 mph (48 km/h) 01 hours 13 minutes
40 mph (64 km/h) 00 hours 55 minutes
50 mph (80 km/h) 00 hours 44 minutes
60 mph (97 km/h) 00 hours 36 minutes
70 mph (112 km/h) 00 hours 31 minutes
75 mph (120 km/h) 00 hours 29 minutes
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