Distance Calculator

Distance from Searcy to Zapopan

Distance between Searcy and Zapopan is 1976 kilometers (1228 miles).
Driving distance from Searcy to Zapopan is 2304 kilometers (1432 miles).

air 1976 km
air 1228 miles
car 2304 km
car 1432 miles

Distance Map Between Searcy and Zapopan

Searcy, Little Rock, United StatesZapopan, Guadalajara, Mexico = 1228 miles = 1976 km.

How far is it between Searcy and Zapopan

Searcy is located in United States with (35.2506,-91.7363) coordinates and Zapopan is located in Mexico with (20.7236,-103.3848) coordinates. The calculated flying distance from Searcy to Zapopan is equal to 1228 miles which is equal to 1976 km.

If you want to go by car, the driving distance between Searcy and Zapopan is 2304.1 km. If you ride your car with an average speed of 112 kilometers/hour (70 miles/h), travel time will be 20 hours 34 minutes. Please check the avg. speed travel time table on the right for various options.
Difference between fly and go by a car is 328 km.

City/PlaceLatitude and LongitudeGPS Coordinates
Searcy 35.2506, -91.7363 35° 15´ 2.3040'' N
91° 44´ 10.5000'' W
Zapopan 20.7236, -103.3848 20° 43´ 24.8160'' N
103° 23´ 5.2440'' W

Estimated Travel Time Between Searcy and Zapopan

Average SpeedTravel Time
30 mph (48 km/h) 48 hours 00 minutes
40 mph (64 km/h) 36 hours 00 minutes
50 mph (80 km/h) 28 hours 48 minutes
60 mph (97 km/h) 23 hours 45 minutes
70 mph (112 km/h) 20 hours 34 minutes
75 mph (120 km/h) 19 hours 12 minutes
Zapopan, Guadalajara, Mexico

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