Distance Calculator

Distance from Seymour to Gatineau

Distance between Seymour and Gatineau is 501 kilometers (311 miles).
Driving distance from Seymour to Gatineau is 719 kilometers (447 miles).

air 501 km
air 311 miles
car 719 km
car 447 miles

Distance Map Between Seymour and Gatineau

Seymour, Hartford, United StatesGatineau, Quebec, Canada = 311 miles = 501 km.

How far is it between Seymour and Gatineau

Seymour is located in United States with (41.3968,-73.0759) coordinates and Gatineau is located in Canada with (45.4772,-75.7016) coordinates. The calculated flying distance from Seymour to Gatineau is equal to 311 miles which is equal to 501 km.

If you want to go by car, the driving distance between Seymour and Gatineau is 719.43 km. If you ride your car with an average speed of 112 kilometers/hour (70 miles/h), travel time will be 06 hours 25 minutes. Please check the avg. speed travel time table on the right for various options.
Difference between fly and go by a car is 218 km.

City/PlaceLatitude and LongitudeGPS Coordinates
Seymour 41.3968, -73.0759 41° 23´ 48.3360'' N
73° 4´ 33.3840'' W
Gatineau 45.4772, -75.7016 45° 28´ 38.0280'' N
75° 42´ 5.9040'' W

Estimated Travel Time Between Seymour and Gatineau

Average SpeedTravel Time
30 mph (48 km/h) 14 hours 59 minutes
40 mph (64 km/h) 11 hours 14 minutes
50 mph (80 km/h) 08 hours 59 minutes
60 mph (97 km/h) 07 hours 25 minutes
70 mph (112 km/h) 06 hours 25 minutes
75 mph (120 km/h) 05 hours 59 minutes
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