Distance Calculator

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Distance from Seymour to Plainville

Distance between Seymour and Plainville is 36 kilometers (22 miles).
Driving distance from Seymour to Plainville is 48 kilometers (30 miles).

air 36 km
air 22 miles
car 48 km
car 30 miles

Distance Map Between Seymour and Plainville

Seymour, Hartford, United StatesPlainville, Hartford, United States = 22 miles = 36 km.

How far is it between Seymour and Plainville

Seymour is located in United States with (41.3968,-73.0759) coordinates and Plainville is located in United States with (41.6745,-72.8582) coordinates. The calculated flying distance from Seymour to Plainville is equal to 22 miles which is equal to 36 km.

If you want to go by car, the driving distance between Seymour and Plainville is 48.18 km. If you ride your car with an average speed of 112 kilometers/hour (70 miles/h), travel time will be 00 hours 25 minutes. Please check the avg. speed travel time table on the right for various options.
Difference between fly and go by a car is 12 km.

City/PlaceLatitude and LongitudeGPS Coordinates
Seymour 41.3968, -73.0759 41° 23´ 48.3360'' N
73° 4´ 33.3840'' W
Plainville 41.6745, -72.8582 41° 40´ 28.3440'' N
72° 51´ 29.3760'' W

Estimated Travel Time Between Seymour and Plainville

Average SpeedTravel Time
30 mph (48 km/h) 01 hours 00 minutes
40 mph (64 km/h) 00 hours 45 minutes
50 mph (80 km/h) 00 hours 36 minutes
60 mph (97 km/h) 00 hours 29 minutes
70 mph (112 km/h) 00 hours 25 minutes
75 mph (120 km/h) 00 hours 24 minutes

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