Distance Calculator

Distance from Seymour to Evansville

Distance between Seymour and Evansville is 182 kilometers (113 miles).
Driving distance from Seymour to Evansville is 265 kilometers (165 miles).

air 182 km
air 113 miles
car 265 km
car 165 miles

Distance Map Between Seymour and Evansville

Seymour, Indianapolis, United StatesEvansville, Indianapolis, United States = 113 miles = 182 km.

How far is it between Seymour and Evansville

Seymour is located in United States with (38.9592,-85.8903) coordinates and Evansville is located in United States with (37.9748,-87.5559) coordinates. The calculated flying distance from Seymour to Evansville is equal to 113 miles which is equal to 182 km.

If you want to go by car, the driving distance between Seymour and Evansville is 265.24 km. If you ride your car with an average speed of 112 kilometers/hour (70 miles/h), travel time will be 02 hours 22 minutes. Please check the avg. speed travel time table on the right for various options.
Difference between fly and go by a car is 83 km.

City/PlaceLatitude and LongitudeGPS Coordinates
Seymour 38.9592, -85.8903 38° 57´ 33.1920'' N
85° 53´ 24.9000'' W
Evansville 37.9748, -87.5559 37° 58´ 29.1360'' N
87° 33´ 21.0600'' W

Estimated Travel Time Between Seymour and Evansville

Average SpeedTravel Time
30 mph (48 km/h) 05 hours 31 minutes
40 mph (64 km/h) 04 hours 08 minutes
50 mph (80 km/h) 03 hours 18 minutes
60 mph (97 km/h) 02 hours 44 minutes
70 mph (112 km/h) 02 hours 22 minutes
75 mph (120 km/h) 02 hours 12 minutes
Please Share Your Comments