Distance from Seymour to Guadalupe

Distance between Seymour and Guadalupe is 1996 kilometers (1240 miles).
Driving distance from Seymour to Guadalupe is 2360 kilometers (1466 miles).

1996 km

1240 miles

2360 km

1466 miles

Distance Map Between Seymour and Guadalupe

Seymour, Indianapolis, United States ↔ Guadalupe, Monterrey, Mexico = 1240 miles = 1996 km.

How far is it between Seymour and Guadalupe

Seymour is located in United States with (38.9592,-85.8903) coordinates and Guadalupe is located in Mexico with (25.6768,-100.2565) coordinates. The calculated flying distance from Seymour to Guadalupe is equal to 1240 miles which is equal to 1996 km.

If you want to go by car, the driving distance between Seymour and Guadalupe is 2359.55 km. If you ride your car with an average speed of 112 kilometers/hour (70 miles/h), travel time will be 21 hours 04 minutes. Please check the avg. speed travel time table on the right for various options.
Difference between fly and go by a car is 364 km.

City/Place	Latitude and Longitude	GPS Coordinates
Seymour	38.9592, -85.8903	38° 57´ 33.1920'' N 85° 53´ 24.9000'' W
Guadalupe	25.6768, -100.2565	25° 40´ 36.4080'' N 100° 15´ 23.2560'' W

Estimated Travel Time Between Seymour and Guadalupe

Average Speed	Travel Time
30 mph (48 km/h)	49 hours 09 minutes
40 mph (64 km/h)	36 hours 52 minutes
50 mph (80 km/h)	29 hours 29 minutes
60 mph (97 km/h)	24 hours 19 minutes
70 mph (112 km/h)	21 hours 04 minutes
75 mph (120 km/h)	19 hours 39 minutes

Seymour, Indianapolis, United States

Related Distances from Seymour

Cities	Distance
Seymour to Reynosa	2264 km
Seymour to Nuevo Laredo	2126 km
Seymour to Apodaca	2345 km
Seymour to Monterrey	2351 km
Seymour to San Nicolas De Los Garza	2342 km

Guadalupe, Monterrey, Mexico

Related Distances to Guadalupe

Cities	Distance
Valdosta to Guadalupe	2013 km
Warrensburg to Guadalupe	1747 km
Rancho San Diego to Guadalupe	2322 km
Jonesboro to Guadalupe	1648 km
Kirkwood to Guadalupe	1922 km