Distance Calculator

Distance from Tinley Park to Prospect Heights

Distance between Tinley Park and Prospect Heights is 59 kilometers (37 miles).
Driving distance from Tinley Park to Prospect Heights is 79 kilometers (49 miles).

air 59 km
air 37 miles
car 79 km
car 49 miles

Distance Map Between Tinley Park and Prospect Heights

Tinley Park, Springfield, United StatesProspect Heights, Springfield, United States = 37 miles = 59 km.

How far is it between Tinley Park and Prospect Heights

Tinley Park is located in United States with (41.5734,-87.7845) coordinates and Prospect Heights is located in United States with (42.0953,-87.9376) coordinates. The calculated flying distance from Tinley Park to Prospect Heights is equal to 37 miles which is equal to 59 km.

If you want to go by car, the driving distance between Tinley Park and Prospect Heights is 79.48 km. If you ride your car with an average speed of 112 kilometers/hour (70 miles/h), travel time will be 00 hours 42 minutes. Please check the avg. speed travel time table on the right for various options.
Difference between fly and go by a car is 20 km.

City/PlaceLatitude and LongitudeGPS Coordinates
Tinley Park 41.5734, -87.7845 41° 34´ 24.1320'' N
87° 47´ 4.1640'' W
Prospect Heights 42.0953, -87.9376 42° 5´ 43.0800'' N
87° 56´ 15.2520'' W

Estimated Travel Time Between Tinley Park and Prospect Heights

Average SpeedTravel Time
30 mph (48 km/h) 01 hours 39 minutes
40 mph (64 km/h) 01 hours 14 minutes
50 mph (80 km/h) 00 hours 59 minutes
60 mph (97 km/h) 00 hours 49 minutes
70 mph (112 km/h) 00 hours 42 minutes
75 mph (120 km/h) 00 hours 39 minutes
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