Distance Calculator

Distance from Tinley Park to Vaughan

Distance between Tinley Park and Vaughan is 722 kilometers (449 miles).
Driving distance from Tinley Park to Vaughan is 832 kilometers (517 miles).

air 722 km
air 449 miles
car 832 km
car 517 miles

Distance Map Between Tinley Park and Vaughan

Tinley Park, Springfield, United StatesVaughan, Ontario, Canada = 449 miles = 722 km.

How far is it between Tinley Park and Vaughan

Tinley Park is located in United States with (41.5734,-87.7845) coordinates and Vaughan is located in Canada with (43.8361,-79.4983) coordinates. The calculated flying distance from Tinley Park to Vaughan is equal to 449 miles which is equal to 722 km.

If you want to go by car, the driving distance between Tinley Park and Vaughan is 831.87 km. If you ride your car with an average speed of 112 kilometers/hour (70 miles/h), travel time will be 07 hours 25 minutes. Please check the avg. speed travel time table on the right for various options.
Difference between fly and go by a car is 110 km.

City/PlaceLatitude and LongitudeGPS Coordinates
Tinley Park 41.5734, -87.7845 41° 34´ 24.1320'' N
87° 47´ 4.1640'' W
Vaughan 43.8361, -79.4983 43° 50´ 9.9600'' N
79° 29´ 53.7720'' W

Estimated Travel Time Between Tinley Park and Vaughan

Average SpeedTravel Time
30 mph (48 km/h) 17 hours 19 minutes
40 mph (64 km/h) 12 hours 59 minutes
50 mph (80 km/h) 10 hours 23 minutes
60 mph (97 km/h) 08 hours 34 minutes
70 mph (112 km/h) 07 hours 25 minutes
75 mph (120 km/h) 06 hours 55 minutes
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