Distance Calculator

Distance from Tinton Falls to Sayreville

Distance between Tinton Falls and Sayreville is 28 kilometers (17 miles).
Driving distance from Tinton Falls to Sayreville is 39 kilometers (24 miles).

air 28 km
air 17 miles
car 39 km
car 24 miles

Distance Map Between Tinton Falls and Sayreville

Tinton Falls, Trenton, United StatesSayreville, Trenton, United States = 17 miles = 28 km.

How far is it between Tinton Falls and Sayreville

Tinton Falls is located in United States with (40.3043,-74.1004) coordinates and Sayreville is located in United States with (40.4593,-74.361) coordinates. The calculated flying distance from Tinton Falls to Sayreville is equal to 17 miles which is equal to 28 km.

If you want to go by car, the driving distance between Tinton Falls and Sayreville is 39.28 km. If you ride your car with an average speed of 112 kilometers/hour (70 miles/h), travel time will be 00 hours 21 minutes. Please check the avg. speed travel time table on the right for various options.
Difference between fly and go by a car is 11 km.

City/PlaceLatitude and LongitudeGPS Coordinates
Tinton Falls 40.3043, -74.1004 40° 18´ 15.4080'' N
74° 6´ 1.5120'' W
Sayreville 40.4593, -74.361 40° 27´ 33.3720'' N
74° 21´ 39.5280'' W

Estimated Travel Time Between Tinton Falls and Sayreville

Average SpeedTravel Time
30 mph (48 km/h) 00 hours 49 minutes
40 mph (64 km/h) 00 hours 36 minutes
50 mph (80 km/h) 00 hours 29 minutes
60 mph (97 km/h) 00 hours 24 minutes
70 mph (112 km/h) 00 hours 21 minutes
75 mph (120 km/h) 00 hours 19 minutes
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