Distance from Victorville to San Jose
Distance between Victorville and San Jose is 518 kilometers (322 miles).
Driving distance from Victorville to San Jose is 605 kilometers (376 miles).
Distance Map Between Victorville and San Jose
Victorville, Sacramento, United States ↔ San Jose, Sacramento, United States = 322 miles = 518 km.
How far is it between Victorville and San Jose
Victorville is located in United States with (34.5361,-117.2912) coordinates and San Jose is located in United States with (37.3394,-121.895) coordinates. The calculated flying distance from Victorville to San Jose is equal to 322 miles which is equal to 518 km.
If you want to go by car, the driving distance between Victorville and San Jose is 604.63 km. If you ride your car with an average speed of 112 kilometers/hour (70 miles/h), travel time will be 05 hours 23 minutes. Please check the avg. speed travel time table on the right for various options.
Difference between fly and go by a car is 87 km.
City/Place | Latitude and Longitude | GPS Coordinates |
---|---|---|
Victorville | 34.5361, -117.2912 | 34° 32´ 9.9960'' N 117° 17´ 28.1760'' W |
San Jose | 37.3394, -121.895 | 37° 20´ 21.8040'' N 121° 53´ 41.8560'' W |
Estimated Travel Time Between Victorville and San Jose
Average Speed | Travel Time |
---|---|
30 mph (48 km/h) | 12 hours 35 minutes |
40 mph (64 km/h) | 09 hours 26 minutes |
50 mph (80 km/h) | 07 hours 33 minutes |
60 mph (97 km/h) | 06 hours 13 minutes |
70 mph (112 km/h) | 05 hours 23 minutes |
75 mph (120 km/h) | 05 hours 02 minutes |
Related Distances from Victorville
Cities | Distance |
---|---|
Victorville to Oakdale 2 | 551 km |
Victorville to San Rafael 2 | 687 km |
Victorville to Oroville | 772 km |
Victorville to Hacienda Heights | 117 km |
Victorville to Inglewood | 159 km |
Related Distances to San Jose
Cities | Distance |
---|---|
Walnut Park to San Jose | 559 km |
Walnut Creek to San Jose | 81 km |
Tracy to San Jose | 99 km |
Tustin to San Jose | 601 km |
San Luis Obispo to San Jose | 298 km |