Distance Calculator

Distance from Warrensburg to Columbia

Distance between Warrensburg and Columbia is 123 kilometers (77 miles).
Driving distance from Warrensburg to Columbia is 152 kilometers (95 miles).

air 123 km
air 77 miles
car 152 km
car 95 miles

Distance Map Between Warrensburg and Columbia

Warrensburg, Jefferson City, United StatesColumbia, Jefferson City, United States = 77 miles = 123 km.

How far is it between Warrensburg and Columbia

Warrensburg is located in United States with (38.7628,-93.7361) coordinates and Columbia is located in United States with (38.9517,-92.3341) coordinates. The calculated flying distance from Warrensburg to Columbia is equal to 77 miles which is equal to 123 km.

If you want to go by car, the driving distance between Warrensburg and Columbia is 152.36 km. If you ride your car with an average speed of 112 kilometers/hour (70 miles/h), travel time will be 01 hours 21 minutes. Please check the avg. speed travel time table on the right for various options.
Difference between fly and go by a car is 29 km.

City/PlaceLatitude and LongitudeGPS Coordinates
Warrensburg 38.7628, -93.7361 38° 45´ 46.0440'' N
93° 44´ 9.7800'' W
Columbia 38.9517, -92.3341 38° 57´ 6.1560'' N
92° 20´ 2.6520'' W

Estimated Travel Time Between Warrensburg and Columbia

Average SpeedTravel Time
30 mph (48 km/h) 03 hours 10 minutes
40 mph (64 km/h) 02 hours 22 minutes
50 mph (80 km/h) 01 hours 54 minutes
60 mph (97 km/h) 01 hours 34 minutes
70 mph (112 km/h) 01 hours 21 minutes
75 mph (120 km/h) 01 hours 16 minutes
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