Distance from Warrensburg to Liberty

Distance between Warrensburg and Liberty is 80 kilometers (50 miles).
Driving distance from Warrensburg to Liberty is 105 kilometers (65 miles).

80 km

50 miles

105 km

65 miles

Distance Map Between Warrensburg and Liberty

Warrensburg, Jefferson City, United States ↔ Liberty, Jefferson City, United States = 50 miles = 80 km.

How far is it between Warrensburg and Liberty

Warrensburg is located in United States with (38.7628,-93.7361) coordinates and Liberty is located in United States with (39.2461,-94.4191) coordinates. The calculated flying distance from Warrensburg to Liberty is equal to 50 miles which is equal to 80 km.

If you want to go by car, the driving distance between Warrensburg and Liberty is 104.71 km. If you ride your car with an average speed of 112 kilometers/hour (70 miles/h), travel time will be 00 hours 56 minutes. Please check the avg. speed travel time table on the right for various options.
Difference between fly and go by a car is 25 km.

City/Place	Latitude and Longitude	GPS Coordinates
Warrensburg	38.7628, -93.7361	38° 45´ 46.0440'' N 93° 44´ 9.7800'' W
Liberty	39.2461, -94.4191	39° 14´ 45.9960'' N 94° 25´ 8.8320'' W

Estimated Travel Time Between Warrensburg and Liberty

Average Speed	Travel Time
30 mph (48 km/h)	02 hours 10 minutes
40 mph (64 km/h)	01 hours 38 minutes
50 mph (80 km/h)	01 hours 18 minutes
60 mph (97 km/h)	01 hours 04 minutes
70 mph (112 km/h)	00 hours 56 minutes
75 mph (120 km/h)	00 hours 52 minutes

Warrensburg, Jefferson City, United States

Related Distances from Warrensburg

Cities	Distance
Warrensburg to Saint Joseph	186 km
Warrensburg to Kirkwood	333 km
Warrensburg to Arnold 3	356 km
Warrensburg to East Independence	90 km
Warrensburg to Maryland Heights	326 km

Liberty, Jefferson City, United States

Related Distances to Liberty

Cities	Distance
Naperville to Libertyville	78 km
Palatine to Libertyville	25 km
Raymore to Liberty	61 km
Oak Park to Libertyville	66 km
Plainfield 2 to Libertyville	98 km