Distance from Warrensburg to Ozark

Distance between Warrensburg and Ozark is 199 kilometers (124 miles).
Driving distance from Warrensburg to Ozark is 219 kilometers (136 miles).

199 km

124 miles

219 km

136 miles

Distance Map Between Warrensburg and Ozark

Warrensburg, Jefferson City, United States ↔ Ozark, Jefferson City, United States = 124 miles = 199 km.

How far is it between Warrensburg and Ozark

Warrensburg is located in United States with (38.7628,-93.7361) coordinates and Ozark is located in United States with (37.0209,-93.206) coordinates. The calculated flying distance from Warrensburg to Ozark is equal to 124 miles which is equal to 199 km.

If you want to go by car, the driving distance between Warrensburg and Ozark is 218.52 km. If you ride your car with an average speed of 112 kilometers/hour (70 miles/h), travel time will be 01 hours 57 minutes. Please check the avg. speed travel time table on the right for various options.
Difference between fly and go by a car is 20 km.

City/Place	Latitude and Longitude	GPS Coordinates
Warrensburg	38.7628, -93.7361	38° 45´ 46.0440'' N 93° 44´ 9.7800'' W
Ozark	37.0209, -93.206	37° 1´ 15.2040'' N 93° 12´ 21.6720'' W

Estimated Travel Time Between Warrensburg and Ozark

Average Speed	Travel Time
30 mph (48 km/h)	04 hours 33 minutes
40 mph (64 km/h)	03 hours 24 minutes
50 mph (80 km/h)	02 hours 43 minutes
60 mph (97 km/h)	02 hours 15 minutes
70 mph (112 km/h)	01 hours 57 minutes
75 mph (120 km/h)	01 hours 49 minutes

Warrensburg, Jefferson City, United States

Related Distances from Warrensburg

Cities	Distance
Warrensburg to Ozark	219 km
Warrensburg to Nixa	223 km
Warrensburg to Raytown	77 km
Warrensburg to Cape Girardeau	514 km
Warrensburg to Ferguson	336 km

Ozark, Jefferson City, United States

Related Distances to Ozark

Cities	Distance
Saint Charles to Ozark	376 km
Kirksville to Ozark	432 km
Fort Leonard Wood to Ozark	166 km
Sikeston to Ozark	372 km
Spanish Lake to Ozark	385 km