Distance Calculator

Distance from Waterbury to Seymour

Distance between Waterbury and Seymour is 18 kilometers (11 miles).
Driving distance from Waterbury to Seymour is 20 kilometers (12 miles).

air 18 km
air 11 miles
car 20 km
car 12 miles

Distance Map Between Waterbury and Seymour

Waterbury, Hartford, United StatesSeymour, Hartford, United States = 11 miles = 18 km.

How far is it between Waterbury and Seymour

Waterbury is located in United States with (41.5582,-73.0515) coordinates and Seymour is located in United States with (41.3968,-73.0759) coordinates. The calculated flying distance from Waterbury to Seymour is equal to 11 miles which is equal to 18 km.

If you want to go by car, the driving distance between Waterbury and Seymour is 20.11 km. If you ride your car with an average speed of 112 kilometers/hour (70 miles/h), travel time will be 00 hours 10 minutes. Please check the avg. speed travel time table on the right for various options.
Difference between fly and go by a car is 2 km.

City/PlaceLatitude and LongitudeGPS Coordinates
Waterbury 41.5582, -73.0515 41° 33´ 29.3400'' N
73° 3´ 5.4000'' W
Seymour 41.3968, -73.0759 41° 23´ 48.3360'' N
73° 4´ 33.3840'' W

Estimated Travel Time Between Waterbury and Seymour

Average SpeedTravel Time
30 mph (48 km/h) 00 hours 25 minutes
40 mph (64 km/h) 00 hours 18 minutes
50 mph (80 km/h) 00 hours 15 minutes
60 mph (97 km/h) 00 hours 12 minutes
70 mph (112 km/h) 00 hours 10 minutes
75 mph (120 km/h) 00 hours 10 minutes
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